## Given an array `A`

of integers, for each integer `A[i]`

we may choose any `x`

with `-K <= x <= K`

, and add `x`

to `A[i]`

.

After this process, we have some array `B`

.

Return the smallest possible difference between the maximum value of `B`

and the minimum value of `B`

.

## Solution

If we want to find the smallest possible difference between max(B) and min(B), we will have to try to minimize max(B) - min(B). We should try to minimize max(B), then maximize min(B).

The smallest possible value of max(B) is max(A) - K since - K is the most we can subtract from max(A). Similarly, the largest possible value of min(B) is min(A) + K since K is the most we can add to min(A). So the smallest we can make max(B) - min(B) is (max(A) - K) - (min(A) + K) = *max(A) - min(A) - 2K*.